System visual reasoning data

Our STEM Reasoning Dataset is a curated collection of image-based and diagram-driven tasks spanning Physics, Chemistry, and Mathematics. This dataset is designed to train and evaluate a model’s ability to perform logical deduction, symbolic matching, and visual-spatial inference across scientific disciplines.

Each task includes carefully structured visuals such as scientific diagrams, equations, and problem scenarios, accompanied by questions and structured answers. The dataset emphasizes conceptual understanding and analytical reasoning, making it ideal for AI models focused on education, tutoring, or scientific problem-solving. We also offer customization options to align the content with your curriculum or evaluation framework, ensuring maximum relevance for your use case.

Sample Data

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Subject: Chemistry

Sample Transcription

[
  {
    "question_id": "1",
    "images": [
      "https://storage.googleapis.com/joshtalks-data-collection-248zy39c/jee_data/mcq_pair_image/image71.jpg"
    ],
    "question_statement": "The cell potential for the following unbalanced redox reaction:
<latex>Hg22+(aq)+NO3−(aq)+3H3O+(aq)→2Hg2+(aq)+HNO2(aq)+4H2O(l)</latex> is measured under standard conditions using an electrochemical cell diagram.
[https://storage.googleapis.com/joshtalks-data-collection-248zy39c/jee_data/mcq_pair_image/image71.jpg]
Figure above
How many moles of electrons are transferred through the external circuit if 0.60 mol of <latex>Hg2+</latex> and 0.30 mol of <latex>HNO2</latex> are formed from a cell containing 0.50 mol of <latex>Hg2 2+</latex> and 0.40 mol of <latex>NO3 −</latex>at the beginning? In which dish is the solution acidic?",
    "options": {
      "A": "0.30 mol , Dish A",
      "B": "0.60 mol , Dish B",
      "C": "0.15 mol , Dish B",
      "D": "1.20 mol , Dish A"
    },
    "problem_statement_analysis": "Balanced cathodic half-reaction:
<latex>NO3−+3H3O++2e−→HNO2+4H2O</latex>
Each mole of <latex>HNO2</latex> formed involves 2 electrons.
--	<latex>H3O+</latex>(hydronium) is present only on the reactant side, required to reduce <latex>NO3 −</latex>to <latex>HNO2</latex>.
--	Therefore, the half-reaction involving <latex>NO3 −</latex>occurs in an acidic medium.",
    "step_by_step_explanation": "Given:
Moles of <latex>HNO2</latex> formed <latex>=0.30 mol</latex>
<latex> Moles of electrons =2×0.30=0.60 mol</latex>
<latex>NO3 −</latex>is getting reduced, so this occurs at the cathode (i.e., Dish B).
Dish B must be acidic, due to requirement of <latex>H3O+</latex>ions.",
    "final_answer_summary": "Mole of electrons formed <latex>=0.60 mol</latex>
Correct Answer : (B) <latex>0.60 mol</latex>, Dish B",
    "subject": "Chemistry",
    "topic": "Electrochemistry - Galvanic Cells and Redox Stoichiometry",
    "difficulty_level": "5",
    "answer_type": "Multiple Parts (MCQs with explanation)",
    "question_type": "Conceptual + Redox Stoichiometry",
    "tags": [
      "Standard electrode potential",
      "electron transfer",
      "acidic medium",
      "redox balancing"
    ],
    "concepts_tested": [
      "Acid-base identification",
      "redox half-reactions",
      "Faraday laws",
      "electron stoichiometry"
    ],
    "figure": "(showing two half-cells: Dish A and Dish B)",
    "common_errors": [
      "Assuming both dishes are neutral",
      "Using wrong electron stoichiometry",
      "Missing <latex>H3O+</latex> "
    ],
    "why_good": "Involves redox analysis, acidic media identification, and quantitative electron flow."
  }